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JonathanKarpick - 25 Aug 2005
Added velocity-dependant (viscous) friction into the model. Coming back to determining trajectories (aka control strategies) led me to the following evolving process which would have to be done for each set of robot characteristics:
- Generate phase plots (over a range of forces) for each state: foot static, falling, foot sliding down, and foot sliding up. Make sure that transition boundaries are depicted.
- Choose trajetory/control strategy that goes (at least) from static to falling and back - check to ensure that the 'bot is actually climbing.
- Optimize?? Somehow...
- Look for limits - i.e., how far can it go in one state and still transition to another state to generate a "closed" (i.e., repeatable) trajetory.
- Is there a way to determine stability of a trajectory?
For this climber, thinking about the possible transitions amongst the states may help determine what trajectories are feasible and possibly help determine a method for determining an "optimal" trajectory given specific physical specifications.
Example trajectory state transitions:
- Static Free Static
- Static Free Sliding Down Static
- Static Sliding Down Free Static
- Static Free Sliding Up Static
- Sliding Down Free Sliding Down
- etc - the only requirement is that each trajectory include the free state... (or maybe sliding up...)
As an example, I'll step through the generation of a trajectory for a system with a viscous friction model between the foot and the pole. First off, parameters:
k = 30; %N/m - Spring constant
b = 4; %N-s/m - Damping constant
neu = 2; %N-s/m - Viscous friction constant
yn = 5; %m - Spring natural length
m = 2; %kg
g = 10; %m/s^2
delta = 2*m*g/3; %Static Friction = mg+delta
zeta = -m*g/10;%Dynamic Friction = mg+zeta
epsilon = m*g/1000; %Karnopp friction deadband level
Flevel = delta; %N
Fs = m*g+delta;
Fd = m*g+zeta;
Phase plots:
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JonathanKarpick - 17 Jun 2005
OneDimClimberNotes.pdf: Updated with quasi-static climbing
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JonathanKarpick - 27 May 2005
Some drawings and a plot of an example trajectory that uses the mass to add and control energy in the system and get the foot moving up the pole:
OneDimClimber-QtrReport.ppt:
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JonathanKarpick - 13 May 2005
I've been working on a semi-formal write-up of this model for distribution. The current version is attached here:
OneDimClimberNotes.pdf
I still have some thinking to do about transitioning from sliding to clamped and then tying trajectories together for a closed cycle. And of course, how everything ties together to foot height, since that's the object of the whole thing.
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JonathanKarpick - 06 May 2005
Quick chat with Dan Santos after today's
RiSE Telecon led to some good questions:
- Is there ever a time when you can actually stop the climber from sliding down the pole once it starts?
- From calculations yesterday, the transition from free to clamped can only work when the velocity of the mass is less than a certain level ( to be exact) - WHICH DOESN'T DEPEND ON THE FORCE APPLIED and the spring extension is less than a certain level (which does depend on the force: )
- For a transition from sliding down to clamped to work, it must occur at a point that meets the same conditions.
- Actually, those equations are only sufficient, because I am assuming that the transition from Free to Clamped occurs on the Clamped-to-Sliding Down boundary. If the transition occurs off of this boundary, the criteria is that the resulting trajectory cannot cross the boundary.
- What are the boundary cases?
- What are the restrictions on the relations between m, k, b, Fs, F, Fd for different boundary cases or climbing methods?
.
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JonathanKarpick - 05 May 2005
Re-did the phase portraits for the (now) six states. I've split up the clamped state into three states for clamped with F=+, clamped with F=0, clamped with F=-. Actually, I just went and generated phase portraits for Free, Clamped, Sliding Up, and Sliding Down, all with the three possibilities of force application {+,0,-}.
Lessons learned today are that the transition from Free to Clamped must occur at a point such that the resulting Clamped trajectory doesn't break the static friction force limit. One way to do this is to let the free state go until that force limit line (depicted on the Free state portraits). The free trajectory must hit this line at a point where the clamped trajectory pushes back into the first quadrant. This effectively gives a minimum
(or maximum
depending upon your point of view) which puts on a condition on the entrance to the Free state to begin with...
Also, the Sliding Down state will likely use a positive force application to keep the steady state spring length near zero.
The goal becomes how to switch among the following phase portraits such that the climber actually moves up the pole.
In the clamped state, transitioning from F=22 to F=0 to F=-22 as you near the sliding down boundary (for x-dot < 0) doesn't appear to do much good... The blue line is the transition from clamped to sliding down. The green line is the transition from clamped to sliding up.
Using F=-22 (negative) is probably best, since it pushes you into the better part of the clamped phase plot for after the clamp... The blue line depicts the transition from clamped to sliding down when F=22. In fact, there is a specific curve for each of these plots which separates trajectories that will work in the clamped state from those that won't (assuming you transition at the blue line). The boundary trajectory can be found by locating the point along the blue line where (in the clamped state):
and then following the trajectory in the free state that intersects this point. Transitions into the Free state above this trajectory can be successfully re-clamped, while those that transition below this trajectory will end up sliding down...
For this configuration, that end-point on the blue line is
,
for clamped state with F=22N.
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JonathanKarpick - 28 Apr 2005
In order to have trajectories without any slipping, the transition from free to clamped must occur before a transition to clamped would cause slipping (i.e., before the mass is falling too quickly...) This can be done by re-clamping when
A sample trajectory and z time history are shown here:
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JonathanKarpick - 22 Apr 2005
State Phase Portraits and Transitions:
Transition to sliding down:
Transition to sliding up:
Transition to free:
AND
Transition to clamped:
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JonathanKarpick - 18 Apr 2005
Note: a PDF version of this page is attached here:
OneDOFClimberNotes.pdf - the equations are a little cleaner in the PDF file.
The one degree-of-freedom climber is an example cooked up between myself, Mark, and Dan Santos about what a really simple climber could look like:
The climber consists of a body connected to a (mass-less) foot via a spring, damper, and force actuator in parallel. The foot can clamp onto a vertical pole with a given clamping (normal) force, or release the pole. Gravity acts down the pole:
There is Coulumb friction between the clamp and the pole when the climber has clamped the pole. The static friction limit is slightly more than the weight of the climber
and the kinetic friction force generated when sliding is slightly less than the weight of the climber
Variables:
- absolute coordinate of the body
- relative coordinate from body to foot
- uncompressed length of spring
- absolute coordinate of the foot,
- amount of spring extension,
- mass of climber
- gravity
- actuator force
- wall force applied to foot (friction force)
- spring constant
- damping constant
Equations when clamped and not sliding:
Equations when not clamped:
Equations when sliding down:
Equations when sliding up:
Transitions:
From clamped to free when
and
, set
(retract foot)
From clamped to sliding down when
, set
,
(give foot a small downward velocity), and
(try to make
positive)
From clamped to sliding up when
, set
,
(give foot a small downward velocity), and
(retract foot)
From free to clamped when
, set
,
, and
(extend foot)
From sliding down to clamped when
, set
and
(extend foot)
From sliding up to clamped when
, set
and
(extend foot)
Some observations:
to prevent sliding when you apply the force when the entire system is at rest.
The force applications given above for each state are intended in all cases to get (or keep) the foot moving up the pole.
To do:
- Put up some drawings in here
- Simulate a system with no friction limit and look at trajectories (use Matlab's LMI??)
- Simulate system with friction limits and look at trajectories